Molecular Genetics

Molecular Genetics / Nucleic acids / DNA replication&transcription / Genetic code / mRNA translation

Molecular Genetics / Nucleic acids / DNA replication&transcription / Genetic code / mRNA translation


A. M.
This flashcard set delves into the intricate processes of molecular genetics at a university level, focusing on DNA, RNA, and protein synthesis. It covers key concepts like replication, transcription, translation, and the roles of enzymes such as polymerase and helicase. The flashcards also explore genetic codes, codons, and the structure of nucleic acids. Ideal for students and professionals in medical and biological sciences, this set provides a comprehensive understanding of molecular genetics, essential for grasping advanced biological principles.
Cartes-fiches
180
Utilisateurs
6
Langue
Anglais
Catégorie
Médecine
Niveau
Université
Créé / Mis à jour
01.01.2017 / 08.11.2019

Cartes-fiches

What is the name of the enzyme responsible for ….. the DNA molecule for replication

Which of the following are correctly associated:

The enzyme called peptidyl transferase catalyzes the formation of:

Indicate the correct stages of chromatin condensation:

The genetic code is commaless because:

A, B, C and D in the picture represent

 

…. DNA transcription occurs in:

The enzyme catalysing the attachment of an amino acids to the tRNAs …:

In the picture below arrows number 1 indicate template strands the other number are:

 

 

 

At which position of the deoxyribose ring is the nitrogenous base attached:

 

C4: phosphate group

ATTThe triplet base sequence in DNA template strand that is translated into a stop codon is:

The lac repressor protein binds to the operator region:

Which of the following are not correctly associated:

The result of the transcription process is:

Which of the following statements is true:

The operator gene of the lac operon:

RNA molecule is:

The other name of the prokaryotic elongation factor EF-G:

The enzyme of RNA polymerase participates in which process?:

The genetic code is non-overlapping because:

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